GoFuckYourself.com - Adult Webmaster Forum - View Single Post - Math problem... solving for a variable thats an exponent

AmigoPorn · 06-04-2006, 10:42 PM

1.08^-n + 1.08^-2n = 1

1 + 1.08^-n = 1 ( 1.08^n )

-1.08^n + 1.08^-n + 1 = 0

-1.08^n + 1 / ( 1.08^n ) + 1 = 0

-1.08^2n + 2 = 0

1.08^2n = 2

2n = log 2 / log 1.08

2n = 9.006468342

n = 4.503234171

06-04-2006, 10:42 PM
AmigoPorn Too lazy to set a custom title Join Date: Jul 2003 Location: Mexico - So far away from god, so close to the United States Posts: 21,583	1.08^-n + 1.08^-2n = 1 1 + 1.08^-n = 1 ( 1.08^n ) -1.08^n + 1.08^-n + 1 = 0 -1.08^n + 1 / ( 1.08^n ) + 1 = 0 -1.08^2n + 2 = 0 1.08^2n = 2 2n = log 2 / log 1.08 2n = 9.006468342 n = 4.503234171 __________________ ICQ: 267899523