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Overload · 12-12-2010, 10:39 AM

who caused this shit in the first place? the last "big count" of the mayans ends, thats ALL! there is NO prediction of "doom" of any kind from the maya ... yaya, now some come gabbing about "planetary lineup" crap ... do your maths; geez ... --->
Let's say we first wanted to determine what the probability would be for all the superior planet's to be at the same right ascension (RA) (i.e., conjunction) and the inferior planets to be exactly 12 hours in RA (=180°) away at the same time. First, we must decide on the span of time we will allow for the planets to be at that location. Instead of setting this to one second, let's allow a little slop and say that the planets have to be at the above mention location within a minute of each other. To do this, we merely multiply the periods of the planets in minutes together (excluding the Earth). This gives:

Probability (planets at same RA at same time) = 1.8 x 10^14 minutes = 3.4 x 10^8 years

Hence, there is one chance in 340 million years that the planet's will all be at the same RA in the sky (with Mercury and Venus 12 hours on the other side of the sky) within a minute of each! Now if we specify that this must occur while the superior planets are at opposition and the inferior planets in inferior conjunction (i.e., the planet's are all at the same RA as seen from the Sun), then we must include the Earth's orbit in the calculation:

Probability (ALL planets at same RA with respect to Sun at same time) =
9.3 x 10^19 minutes = 1.8 x 10^14 years

A whooping once in 180 trillion years!
so ... what could possibly go wrong? lol

12-12-2010, 10:39 AM
Overload Confirmed User Industry Role: Join Date: Jul 2005 Location: Beck's City, North Teutonia Posts: 3,185	who caused this shit in the first place? the last "big count" of the mayans ends, thats ALL! there is NO prediction of "doom" of any kind from the maya ... yaya, now some come gabbing about "planetary lineup" crap ... do your maths; geez ... ---> Let's say we first wanted to determine what the probability would be for all the superior planet's to be at the same right ascension (RA) (i.e., conjunction) and the inferior planets to be exactly 12 hours in RA (=180°) away at the same time. First, we must decide on the span of time we will allow for the planets to be at that location. Instead of setting this to one second, let's allow a little slop and say that the planets have to be at the above mention location within a minute of each other. To do this, we merely multiply the periods of the planets in minutes together (excluding the Earth). This gives: Probability (planets at same RA at same time) = 1.8 x 10^14 minutes = 3.4 x 10^8 years Hence, there is one chance in 340 million years that the planet's will all be at the same RA in the sky (with Mercury and Venus 12 hours on the other side of the sky) within a minute of each! Now if we specify that this must occur while the superior planets are at opposition and the inferior planets in inferior conjunction (i.e., the planet's are all at the same RA as seen from the Sun), then we must include the Earth's orbit in the calculation: Probability (ALL planets at same RA with respect to Sun at same time) = 9.3 x 10^19 minutes = 1.8 x 10^14 years A whooping once in 180 trillion years! so ... what could possibly go wrong? lol __________________ There aren't enough faces and palms on this planet for an appropriate reaction to religion.