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cam_girls · 01-13-2011, 03:06 AM

So you've got

let
a^2 - 2ab + b^2 = c^2 -2cd + d^2

therefore
(a - b)^2 = (c - d)^2

therefore
(a - b) = (c - d)

let a = 1, b = 2, c =4, d = 3

(1 - 2)^2 = (4 - 3)^2

1 = 1

Even though (1 - 2) =/= (4 - 3)

so X^2 = Y^2
-/-> X = Y
(equal squares does not imply equal values)

01-13-2011, 03:06 AM
cam_girls So Fucking Banned Industry Role: Join Date: Apr 2009 Posts: 2,968	So you've got let a^2 - 2ab + b^2 = c^2 -2cd + d^2 therefore (a - b)^2 = (c - d)^2 therefore (a - b) = (c - d) let a = 1, b = 2, c =4, d = 3 (1 - 2)^2 = (4 - 3)^2 1 = 1 Even though (1 - 2) =/= (4 - 3) so X^2 = Y^2 -/-> X = Y (equal squares does not imply equal values)