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sarettah · 10-20-2012, 10:05 AM

$query = "SELECT banner.*, programs.* FROM banner LEFT JOIN programs ON (program_id = programs.id, program = programs.program,)

Do you actually have that comma before the close paren in there. Because that will screw it for you.

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10-20-2012, 10:05 AM
sarettah see you later, I'm gone Industry Role: Join Date: Oct 2002 Posts: 14,057	$query = "SELECT banner., programs. FROM banner LEFT JOIN programs ON (program_id = programs.id, program = programs.program,) Do you actually have that comma before the close paren in there. Because that will screw it for you. . __________________ All cookies cleared!