10-21-2012, 01:30 AM
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Stephen
Industry Role:
Join Date: Jun 2011
Location: Europe
Posts: 840
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Quote:
Originally Posted by Kiopa_Matt
Code:
SELECT banner.id AS banner_id, banner.program_id AS program_id, programs.site AS site_name FROM banner, programs WHERE banner.program_id = programs.id;
You have three columns returned -- banner_id, program_id, site_name. |
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