Quote:
Originally Posted by woj
1. you pick a door, 1/3rd of the time it's a winner... 2/3rds it's not...
2a. IF the chosen door is a winner (1/3rd chance) and you switch = you lose
2b. IF the chosen door is not a winner (2/3rd chance) and you switch = you win
so by using the "switching" strategy, you win 2/3rds of the time...
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wtf - it makes no sense. there are 3 doors - one's been opened and has no car behind it.
now you have two doors left, you having picked one already is meaningless, each door has the same chance of having the car behind it so switching your choice from your first arbitrary one shouldn't increase your odds at all.
obviously i'm wrong but i still don't see it.