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Old 08-29-2021, 07:45 AM  
Publisher Bucks
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Join Date: Oct 2018
Location: New Orleans, Louisiana. / Newcastle, England.
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Quote:
Originally Posted by k33n View Post
Print $sql and make sure the query is valid...i don't think you are passing the $GET['id'] value. And, you say that you want the RecipeID column but you are querying id column, it will fail because your table doesn't have a column "id".
Could you show me where im messing up on that?

I tried changing it in a couple of spots and still running into 500 errors.

(Sorry only been working on php for a couple of months so still pretty green with it).

Thank you for the explanation
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