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- - bash regex or sed help (https://gfy.com/showthread.php?t=1067162)

fris	05-05-2012 09:28 AM

bash regex or sed help

never done regex in bash before, what im bascially trying to do is this perl/php regex

/(\d+)_\d+_\d+[_a-z]*\.jpg/i

what is gets is the facebook profile id, from a facebook image.

http://a1.sphotos.ak.fbcdn.net/hphot...20 4038_n.jpg

would get 80329313253

in php

preg_match('/(\d+)_\d+_\d+[_a-z]*\.jpg/i',$url,$matches);

match[1] would be the fb id

fris	05-05-2012 09:45 AM

actually figured out doing command substituion

Code:

#!/bin/bash



function profile() {

        d=${1#*_}; 

        d=${d#*_}; 

        d=${d%_*}; 

        d=${d%_*}; 

        echo ${d%_*};

}



profile http://a1.sphotos.ak.fbcdn.net/hphotos-ak-ash3/p480x480/558586_10150802565778254_80329313253_9861803_956204038_n.jpg

Barry-xlovecam

05-05-2012 09:45 AM

Code:

sed -i 's/x/y/g'

not /i

fris	05-09-2012 06:11 AM

Quote:

Originally Posted by Barry-xlovecam (Post 18931226)

Code:

sed -i 's/x/y/g'

not /i

got it with sed

Quote:

[fris@fris ~]$ echo "http://a1.sphotos.ak.fbcdn.net/hphotos-ak-ash3/p480x480/558586_10150802565778254_80329313253_9861803_95620 4038_n.jpg" | sed 's/.*_$[0-9]*$_[0-9]*_[0-9]*_n\.jpg$/\1/'
80329313253
[fris@fris ~]$

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