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martinsc

12-24-2005 09:51 AM

[php] - howto update variable in external php file

i need some quick php help...
let's say i have a file called x.php
with a few variables in it

Code:

$a = "2";

$b = "ddd";

and a file called y.php with

Code:

include 'x.php';

how could i get y.php to update the variable value in x.php?

thanks

gornyhuy

12-24-2005 09:52 AM

format c:

Dirty F

12-24-2005 09:52 AM

http://andrejkoymasky.com/liv/fam/bi...01/vand01a.jpg

martinsc

12-24-2005 09:54 AM

thanks for the great help...

RobbieRye

12-24-2005 09:57 AM

If you are declaring constants such as "$a = "2";" then the only way to change it from another script would be to either redeclare it in y.php or re-write x.php using a file write.

There may be other options, but without a more in depth look at your complete script, it's difficult to form them.

martinsc

12-24-2005 09:59 AM

Thanks Robbie.
i'll look into file write.

grumpy

12-24-2005 10:03 AM

do you want to update the var in the file?

who	12-24-2005 10:05 AM

Quote:

Originally Posted by Franck

http://andrejkoymasky.com/liv/fam/bi...01/vand01a.jpg

http://www.celebstation.org/actors/j..._Damme-002.jpg

martinsc

12-24-2005 10:06 AM

Quote:

Originally Posted by grumpy

do you want to update the var in the file?

yes.......

grumpy

12-24-2005 10:12 AM

Quote:

Originally Posted by martinsc

yes.......

then the only thing you can do is rewrite file

easiest thing is every var on a line like
2
3
4

then
$filename = "vars.txt";
$my_vars = file($filename);

$my_vars[0] will be 2

if you have changed the vars

just save the array.

broke

12-24-2005 10:22 AM

You need to open and read the file and then rewrite the contents. Something like this (has not been tested)...

PHP Code:


		
			
$new_value = "6";

$new_file = "";



$handle = @fopen("y.php", "r");

if ($handle) {

   while (!feof($handle)) {

       $buffer = fgets($handle, 4096);

       

       if(stristr($buffer,'$a' !hahahaha FALSE)){

          $new_file .= "$a = ".$new_value."\"";

       } else {

          $new_file .= $buffer;



   }

   fclose($handle);

}



$handle = @fopen("y.php", "w");

if($handle){

   fwrite($handle,$new_file);

}

martinsc

12-24-2005 10:27 AM

thanks a lot guys.
i think i'll go with grumpy's idea...

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