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Myst 06-04-2006 09:33 PM

Math problem... solving for a variable thats an exponent
 
Umm so Im taking an actuarial science course for the spring
I cant for the life of me remember how to do this cause its been so long

how do you solve
1.08^-n + 1.08^-2n = 1

fallenmuffin 06-04-2006 09:43 PM

irc://irc.efnet.net/math

gooddomains 06-04-2006 09:46 PM

1+1=3 :-)

deef-thp 06-04-2006 09:58 PM

-48.830373630755

AmigoPorn 06-04-2006 10:42 PM

1.08^-n + 1.08^-2n = 1

1 + 1.08^-n = 1 ( 1.08^n )

-1.08^n + 1.08^-n + 1 = 0

-1.08^n + 1 / ( 1.08^n ) + 1 = 0

-1.08^2n + 2 = 0

1.08^2n = 2

2n = log 2 / log 1.08

2n = 9.006468342

n = 4.503234171

dave_w 06-04-2006 11:07 PM

Quote:

Originally Posted by AmigoPorn
1.08^-n + 1.08^-2n = 1

1 + 1.08^-n = 1 ( 1.08^n )

-1.08^n + 1.08^-n + 1 = 0

-1.08^n + 1 / ( 1.08^n ) + 1 = 0

-1.08^2n + 2 = 0

1.08^2n = 2

2n = log 2 / log 1.08

2n = 9.006468342

n = 4.503234171


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