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#1 |
Confirmed User
Join Date: Jun 2004
Posts: 597
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Passing two variables localy in php includes
I want to pass
<?php include("http://www.domain.com/site/script.php?go=type&pid=1"); ?> Locally like <?php $go = "type"; $pid = "1"; include("/usr/local/apache/sites/home/domain.com/public_html/site/script.php"); ?> but it doens't work, please help. i can pass "type" but not pid.
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#2 |
Registered User
Join Date: Jul 2003
Location: Florida
Posts: 21
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how are you accessing $go and $pid in script.php?
if you set them the 'local' way like you did above, they won't be in $_REQUEST or any of those variables, but will be like you included the contents of script.php at that point in your file that includes script.php. To test this i created 2 files: included.php and includer.php included.php: <?php print 'one ->'.$one."\n"; print 'two ->'. $two."\n"; ?> includer.php <?php $one='chicken'; $two='1'; include("/path/to/included.php"); ?> ...and the output: one ->chicken two ->1 you may have a variable scope issue, but that's easily worked out... |
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#3 |
Confirmed User
Join Date: Jun 2004
Posts: 597
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I've noticed that I'm only able to pass http://www.domain.com/site/script.php?go because register globals is off so i need to use _GET instead. I have tried this
<?php $go = $_GET['type']; include '/usr/local/apache/sites/home/domain.com/public_html/site/script.php'; ?> but it only passes go without the value http://www.domain.com/site/script.php?go what am i doing wrong?
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#4 |
Confirmed User
Join Date: Jun 2004
Posts: 597
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i fixed it with curl. I don't know how good and effective this is but it works.
<?php $curl_handle=curl_init(); curl_setopt($curl_handle,CURLOPT_URL,'http://www.domain.com/site/script.php?go=type&pid=1'); curl_exec($curl_handle); curl_close($curl_handle); ?>
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