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Don't most people call this Deja Vu?
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Say hi to Captain Kirk for me........
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You give no theory.
I will listen to you when you publish your studies, with accompanying pages of equations and mathematical functions. Until then you can string things together and call them 'proof' as much as you want. |
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again this guy is smoking crack! lol
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STP, STOP, I just figured something, it's all wrong, OMG, it's all WRONG !!!
Demonstration: The coefficients of the power series solutions of certain non-linear differential equations are generated by convolutions of the preceeding coefficients. One example is the differential equation x x'' + a (x')^2 = b (1) Among the solutions of this equation (with appropriate choices of a,b) are exp(t), sin(t), cos(t), (A+Bt)^n, A+Bt+Ct^2, and sqrt(A+Bt+Ct^2). This last function represents the separation between any two objects in unaccelerated motion. Other solutions include the cycloid relation for (non-rotating) gravitational free-fall, and the radial distance of a mass from a central point about which it revolves with constant angular velocity and radial freedom. The power series solution of equation (1) can be written x(t) = c[0] + c[1] t + c[2] t^2 + c[3] t^3 + ... where the coefficients c[i] satisfy the convolutions n / b if n = 2 SUM A(k,n-k) c[k] c[n-k] = ( k=0 \ 0 if n > 2 with A(k,j) = (a-1) j (k-j) + k(k-1)/2 Any choice of c[0], c[1], c[2], and c[3], with c[1]c[2] not zero, determines the values of a,b and therefore all the remaining coefficients. There are many interesting things about these sequences of c[k] values. Focusing on just the sequences with |c[k]| = 1, k=0,1,2,3, there are obviously 16 possible choices, but only 8 up to a simple sign change. These 8 can be arranged as four groups of 2: k I II III IV --- -------- ---------- --------- --------- 0 1 1 -1 1 1 1 1 1 1 1 -1 1 1 1 -1 1 -1 2 1 1 1 -1 -1 -1 1 1 3 -1 1 1 1 -1 1 1 -1 4 1/2 1/2 3/2 -3/2 0 0 1 1 5 1/2 -1/2 5/2 5/2 4/5 -4/5 1 -1 6 -3/2 -3/2 9/2 -9/2 2/5 2/5 1 1 7 3/2 -3/2 19/2 19/2 -2/5 2/5 1 -1 8 3/8 3/8 133/8 -133/8 -1/2 -1/2 1 1 9 -29/8 29/8 267/8 267/8 1/30 -1/30 1 -1 etc Yhe coefficients in each group differ only in sign. The coefficients in groups I and II diverge, and those in group IV are all units. Only the group III sequences converge. Interestingly, these coefficients are given very closely by c[k-1] = 2 exp(ku) sin(kw) for k>2, where u = -0.145370157... / 1.877672951... for III(a) w = ( \ 1.263919649... for III(b) Notice that the two possible values of w sum to 3.1415926... The integer numerators and denominators of these c[k] sequences also have many interesting properties. For example, primes p congruent to +1 (mod 4) first appear in the denominator at c[p], whereas primes congruent to -1 (mod 4) first appear at c[p^2]. The sequence of numerators is much less regular 1 -1 -1 1 0 -4 2 2 -1 -1 59 -9 -1 233 8 -934 49 .. etc Incidentally, the value of b in the ubiquitous equation (1) is essentially just a constant of integration, and the underlying relation is the derivitive x x'' + q x' x'' = 0 where q=3 for unaccelerated separations and q=2 for (non-rotating) gravitational separations. Isolating q and differentiating again leads to the basic relation, free of arbitrary constants, x x' x'' x'''' - x x' (x'')^2 - x (x'')^2 x''' + (x')^2 x'' x''' = 0 Dividing by x x' x'' x''' gives the nice form x'''' x''' x'' x' ------ - ----- - ---- + ----- = 0 x''' x'' x' x see what i mean??? |
I just plugged that into my Transmeta Hyper Accelerator, and wow! I'm posting from the future.
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Fassinating Captain!
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if time exists then you must be already traveling from one point of time to another.
if you say time doesn't exists and that you're always in state of "now" then time traveling isn't an option because "now" expands through the life span. take for instance one of the oldest human languages, sanskrit, it doesnt have past nor future tense. pleople speaking sanskrit believed there is only one continues tense which is "now". |
I have been to the future.
My Name is John Tittor! |
I dream.... therefore I am!
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