Quick php question - GoFuckYourself.com

thunder99 · 06-30-2011, 02:58 AM

I know there's an easy way of doing this, but I'm having a brain freeze.

I want to extract the domain name from this array value

a:1:{s:10:"formfield1";s:17:"www.domain.com";}

Anybody know how?

V_RocKs · 06-30-2011, 03:39 AM

Without or without www.?

Without loading it as JSON shit or whatever that format is...

explode is your friend.

misterhhs · 06-30-2011, 03:52 AM

In my opinion this isn't even correct JSON.
Php has some JSON-functions, these will be the easiest way.

V_RocKs · 06-30-2011, 04:02 AM

This is fucked with by wordpress I am assuming. It has it's own API to pull it back out.

But if it all is in the same format.. just explode it and move on

Soteko · 06-30-2011, 04:27 AM

Code:

	

$sString = 'a:1:{s:10:"formfield1";s:17:"www.domain.com";}';
	
$sTemp = explode(":", $sString);
$iLastIndex = count($sTemp)-1;
	
$sDomain = str_replace( array('"', ';', '}'), "", $sTemp[$iLastIndex]);
echo $sDomain;

Dido · 06-30-2011, 06:22 AM

Quote:

Originally Posted by thunder99

I know there's an easy way of doing this, but I'm having a brain freeze.

I want to extract the domain name from this array value

a:1:{s:10:"formfield1";s:17:"www.domain.com";}

Anybody know how?

This is the way a serialized() array looks like in PHP.
So I guess you could just unserialize() it and then extract $foo['formfield'], which should yield 'www.domain.com'...

[edit]
After actually checking if it would work, I noticed your original isn't formatted properly... the second part claims it's going to contain a string of 17 characters when it's only a 14 character one... so this exact example won't work, but the original of 'www.domain.com' would probably work just fine :P

thunder99 · 06-30-2011, 07:07 AM

Quote:

Originally Posted by Soteko

Code:

	

$sString = 'a:1:{s:10:"formfield1";s:17:"www.domain.com";}';
	
$sTemp = explode(":", $sString);
$iLastIndex = count($sTemp)-1;
	
$sDomain = str_replace( array('"', ';', '}'), "", $sTemp[$iLastIndex]);
echo $sDomain;

I ending up using something similar to this, thanks for the pointers Guys.

Kiopa_Matt · 06-30-2011, 07:18 AM

Above is wrong. Here:

Code:

$sString = 'a:1:{s:10:"formfield1";s:17:"www.domain.com";}';

$vars = unserialize($sString);
$domain = $vars['formfield1'];

EDIT: Sorry, dido got it. Guess I should read the whole thread before replying.

06-30-2011, 02:58 AM	#1
thunder99 Confirmed User Industry Role: Join Date: Nov 2003 Location: Budapest Posts: 503	Quick php question I know there's an easy way of doing this, but I'm having a brain freeze. I want to extract the domain name from this array value a:1:{s:10:"formfield1";s:17:"www.domain.com";} Anybody know how? __________________ yeah, yeah

06-30-2011, 07:18 AM	#8
Kiopa_Matt Confirmed User Industry Role: Join Date: Oct 2007 Posts: 1,448	Above is wrong. Here: Code: $sString = 'a:1:{s:10:"formfield1";s:17:"www.domain.com";}'; $vars = unserialize($sString); $domain = $vars['formfield1']; EDIT: Sorry, dido got it. Guess I should read the whole thread before replying. __________________ xMarkPro -- Ultimate Blog Network Management Streamline your marketing operations. Centralize management of domains, pages, Wordpress blogs, sponsors, link codes, media items, sales and traffic statistics, plus more! Last edited by Kiopa_Matt; 06-30-2011 at 07:20 AM..

06-30-2011, 03:39 AM	#2
V_RocKs Damn Right I Kiss Ass! Industry Role: Join Date: Dec 2003 Location: Cowtown, USA Posts: 32,391	Without or without www.? Without loading it as JSON shit or whatever that format is... explode is your friend.

06-30-2011, 03:52 AM	#3
misterhhs Confirmed User Join Date: Oct 2005 Posts: 165	In my opinion this isn't even correct JSON. Php has some JSON-functions, these will be the easiest way.

06-30-2011, 04:02 AM	#4
V_RocKs Damn Right I Kiss Ass! Industry Role: Join Date: Dec 2003 Location: Cowtown, USA Posts: 32,391	This is fucked with by wordpress I am assuming. It has it's own API to pull it back out. But if it all is in the same format.. just explode it and move on