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Old 04-16-2013, 03:24 PM   #1
Sly
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I need algebra help

A + A(B) = C

I need to solve for A. It's been a while.
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Old 04-16-2013, 03:29 PM   #2
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C/(1+b) ....
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Old 04-16-2013, 03:31 PM   #3
johnnyloadproductions
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Originally Posted by beaner View Post
c/(1+b) ....
a = c/(1+b)

A is the common factor.

You're a Romanian engineer, right?
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Old 04-16-2013, 03:31 PM   #4
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Perfect, thanks.
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Old 04-16-2013, 03:32 PM   #5
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Quote:
Originally Posted by Sly View Post
A + A(B) = C

I need to solve for A. It's been a while.

Beaner's right. Here's the explanation

You need to get A by itself, so that would simplify to A(1+B) = C
(reverse distributive property)

Then divide both sides by (1+B), so A = C/(1+B)
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Old 04-16-2013, 07:23 PM   #6
Socks
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Well, you came to the right place.

Here's what I know about the subject:
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Old 04-16-2013, 07:34 PM   #7
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Quote:
Originally Posted by Sly View Post
A + A(B) = C

I need to solve for A. It's been a while.


A + A(B) = C
<=> a + ab = c
<=> a(1+b) = c
<=> a= c/(1+b)
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Old 04-16-2013, 09:35 PM   #8
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A = 2.64
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Old 04-16-2013, 09:37 PM   #9
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A = .0093 poocoins
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Old 04-16-2013, 09:42 PM   #10
adultmobile
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In A + A(B) = C, the parenthesis around (B) is unnecessary and so confusing, it is A+AB=C... Also you can use wolframalpha that's more cool than GFY offtopics:

http://www.wolframalpha.com/input/?i...AB+%3D+C+for+A

But for the step by step info it asks cash
Fully free it is: http://www.sagemath.org/
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Old 04-16-2013, 09:44 PM   #11
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Quote:
Originally Posted by adultmobile View Post
In A + A(B) = C, the parenthesis around (B) is unnecessary and so confusing, it is A+AB=C... Also you can use wolframalpha that's more cool than GFY offtopics:

http://www.wolframalpha.com/input/?i...AB+%3D+C+for+A

But for the step by step info it asks cash
Fully free it is: http://www.sagemath.org/
damn, you're right, it was the () that was confusing me and i was confused re: why i was confused, thanks for clearing that up!
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