proof that 2 does in fact equal 1 - GoFuckYourself.com

Dawgy · 03-08-2002, 12:57 PM

heh... my 12 year old cousin just sent me this:

i figure im pretty good at algebra, this is all very simple. but i cant figure out what the flaw is in all this, if there is one... haha

Jakke PNG · 03-08-2002, 01:01 PM

You just assume B=1
which it is not.

Jakke PNG · 03-08-2002, 01:02 PM

Actually it's pretty bad otherwise too

Sad to break it to you, but 1=1

Dawgy · 03-08-2002, 01:02 PM

Quote:

Originally posted by TeenGodFather
You just assume B=1
which it is not.

there is no assumption of value... when you end up with 2b = b, u can cancel out the b's, leaving u with 2=1... just like in the steps above, you cancel out the (a-b) on both sides of the equation...

theWatsonian · 03-08-2002, 01:02 PM

Edited because I hate math discussions. One of my closest friends is a rocket scientist out here at EAFB, I get my fill. Have fun.

Jakke PNG · 03-08-2002, 01:03 PM

B is not 1
B could be 19283,333

Dawgy · 03-08-2002, 01:04 PM

yes but you still end up with 2b=b... which is impossible, regardless of value

corvette · 03-08-2002, 01:09 PM

b/b = 1

Jakke PNG · 03-08-2002, 01:10 PM

Quote:

Originally posted by Dawgy
yes but you still end up with 2b=b... which is impossible, regardless of value

Let's do this fun thing and replace A with a value of 3.

A=B
3=3

A²=A*B
3²=3*3

A²-B²=AB-B²
3²-3²=3*3-3²

(A+B)(A-B)=B(a-b)
(3+3)(3-3)=3(3-3)

A+B=B
3+3=3

2B=B
2*3=3

2=1

NO!

I hate when people argue with me when I know I'm right, for example. is 2*3=3?
No.

The damn thing must have been written by a 12-year old.

Jakke PNG · 03-08-2002, 01:11 PM

I have way too much time on my hands.

Oh yeah, I forgot to mention which parts fail but it's mainly the section with ()'s

Dawgy · 03-08-2002, 01:11 PM

Quote:

Originally posted by TeenGodFather
The damn thing must have been written by a 12-year old.

it was

isnt it great when a kid can completely destroy in minutes, everything u know about the universe? haha

NetRodent · 03-08-2002, 01:40 PM

The equation is true only when A and B equal 0.

Jakke PNG · 03-08-2002, 01:44 PM

Quote:

Originally posted by NetRodent
The equation is true only when A and B equal 0.

In which case it comes to 0=0 which is true.

brazz · 03-08-2002, 02:16 PM

Basic math:

If you have an equation and divide both sides by the same factor, the equation remains valid, UNLESS if that factor is zero (remember: "thou shall never divide by zero?")

When you go from (a+b)(a-b) = b(a-b) => a+b = b
you are dividing both sides by (a-b); however, as a=b, (a-b)=0, you are dividing by zero, and the equation loses any validity

Hypo · 03-08-2002, 02:22 PM

Y'all never studied maths. Division by zero is not allowed between steps 4 n 5 -

(a+b)(a-b) = b(a-b)

divide this by (a-b) to get -

a+b = b

but since (a-b) = 0 as a=b, you cant divide by (a-b).

Hypo · 03-08-2002, 02:24 PM

I take that back - Brazz studied maths.

DPlayMax · 03-08-2002, 02:39 PM

a & b = 0

brazz · 03-08-2002, 02:52 PM

Just to try to make it a bit clearer (???):

It´s true that

6 x 3 = 3 x 6
If you divide both sides by 6 or 3, the equation remains true

Now,

10 x 0 = 20 x 0
If you divide both sides by any number, except zero, equalty remains

However, if you divide by zero, you get 10 = 20 (absurd)

Dreamman010 · 03-08-2002, 03:09 PM

Quote:

Originally posted by brazz
Just to try to make it a bit clearer (???):

It´s true that

6 x 3 = 3 x 6
If you divide both sides by 6 or 3, the equation remains true

Now,

10 x 0 = 20 x 0
If you divide both sides by any number, except zero, equalty remains

However, if you divide by zero, you get 10 = 20 (absurd)

That's the problem - you cannot divide by zero at all. Therefore you cannot say "you get 10 = 20" beacuse in fact, you get an undefined number.

TaDoW · 03-08-2002, 03:37 PM

Quote:

Originally posted by brazz
Just to try to make it a bit clearer (???):

It´s true that

6 x 3 = 3 x 6
If you divide both sides by 6 or 3, the equation remains true

Now,

10 x 0 = 20 x 0
If you divide both sides by any number, except zero, equalty remains

However, if you divide by zero, you get 10 = 20 (absurd)

wrong ... anything divided by zero is undefined.

TaDoW · 03-08-2002, 03:41 PM

Quote:

Originally posted by brazz
Basic math:

If you have an equation and divide both sides by the same factor, the equation remains valid, UNLESS if that factor is zero (remember: "thou shall never divide by zero?")

When you go from (a+b)(a-b) = b(a-b) => a+b = b
you are dividing both sides by (a-b); however, as a=b, (a-b)=0, you are dividing by zero, and the equation loses any validity

props to you man =) good call on that, I went halfway through 300 level amath and math in college and didn't pick that up 'till you pointed it out :-)

Mike Semen · 03-08-2002, 04:05 PM

bunky · 04-05-2002, 12:35 PM

i dont give a fuck how old you are, how long u were in school and all that other happy horse shit.. abcdefghijklmnopqrstuvwxyz = zyxvutsrqponmlkjihgfedcba!

bunky

oh and Bump!

03-08-2002, 12:57 PM	#1
Dawgy Confirmed User Join Date: Jul 2001 Posts: 5,856	proof that 2 does in fact equal 1 heh... my 12 year old cousin just sent me this: i figure im pretty good at algebra, this is all very simple. but i cant figure out what the flaw is in all this, if there is one... haha __________________ the revolution is coming.

03-08-2002, 01:01 PM	#2
Jakke PNG ex-TeenGodFather Industry Role: Join Date: Nov 2001 Location: Suomi Finland Perkele Posts: 20,306	You just assume B=1 which it is not. __________________ ..and I'm off.

03-08-2002, 01:02 PM	#3
Jakke PNG ex-TeenGodFather Industry Role: Join Date: Nov 2001 Location: Suomi Finland Perkele Posts: 20,306	Actually it's pretty bad otherwise too Sad to break it to you, but 1=1 __________________ ..and I'm off.

03-08-2002, 01:02 PM	#5
theWatsonian Confirmed User Join Date: Feb 2001 Location: PB4L HQ Posts: 1,737	Edited because I hate math discussions. One of my closest friends is a rocket scientist out here at EAFB, I get my fill. Have fun. __________________ <a href="http://www.watsonian.net"><img src="http://www.watsonian.net/archives/cjpb6.gif" border="0"></a><a href="http://www.adultplatinum.com/wm.html?id=567353"><img src="http://www.watsonian.net/archives/adult_platinum_85x85_03.gif" border="0"></a> Last edited by theWatsonian; 03-08-2002 at 01:06 PM..

03-08-2002, 01:03 PM	#6
Jakke PNG ex-TeenGodFather Industry Role: Join Date: Nov 2001 Location: Suomi Finland Perkele Posts: 20,306	B is not 1 B could be 19283,333 __________________ ..and I'm off.

03-08-2002, 01:04 PM	#7
Dawgy Confirmed User Join Date: Jul 2001 Posts: 5,856	yes but you still end up with 2b=b... which is impossible, regardless of value __________________ the revolution is coming.

03-08-2002, 01:09 PM	#8
corvette Confirmed User Join Date: Oct 2001 Location: scottsdale Posts: 7,880	b/b = 1 __________________ If you need a good company for check writing services, then check out checkissuing, and for webhosting, check out Phoenix NAP

03-08-2002, 01:11 PM	#10
Jakke PNG ex-TeenGodFather Industry Role: Join Date: Nov 2001 Location: Suomi Finland Perkele Posts: 20,306	I have way too much time on my hands. Oh yeah, I forgot to mention which parts fail but it's mainly the section with ()'s __________________ ..and I'm off. Last edited by Jakke PNG; 03-08-2002 at 01:13 PM..

03-08-2002, 01:40 PM	#12
NetRodent Confirmed User Join Date: Jan 2002 Location: In the walls of your house. Posts: 3,985	The equation is true only when A and B equal 0.

03-08-2002, 02:16 PM	#14
brazz Confirmed User Join Date: May 2001 Posts: 135	Basic math: If you have an equation and divide both sides by the same factor, the equation remains valid, UNLESS if that factor is zero (remember: "thou shall never divide by zero?") When you go from (a+b)(a-b) = b(a-b) => a+b = b you are dividing both sides by (a-b); however, as a=b, (a-b)=0, you are dividing by zero, and the equation loses any validity

03-08-2002, 02:22 PM	#15
Hypo So Fucking Banned Join Date: Feb 2001 Posts: 1,104	Y'all never studied maths. Division by zero is not allowed between steps 4 n 5 - (a+b)(a-b) = b(a-b) divide this by (a-b) to get - a+b = b but since (a-b) = 0 as a=b, you cant divide by (a-b).

03-08-2002, 02:24 PM	#16
Hypo So Fucking Banned Join Date: Feb 2001 Posts: 1,104	I take that back - Brazz studied maths.

03-08-2002, 02:39 PM	#17
DPlayMax Confirmed User Join Date: Dec 2001 Location: Phoenix, Arizona Posts: 699	a & b = 0 __________________ The #1 rule of GFY is not to spam other boards. http://www.gofuckyourself.com/gfy_faqs.html

03-08-2002, 02:52 PM	#18
brazz Confirmed User Join Date: May 2001 Posts: 135	Just to try to make it a bit clearer (???): It´s true that 6 x 3 = 3 x 6 If you divide both sides by 6 or 3, the equation remains true Now, 10 x 0 = 20 x 0 If you divide both sides by any number, except zero, equalty remains However, if you divide by zero, you get 10 = 20 (absurd)

03-08-2002, 04:05 PM	#22
Mike Semen Confirmed User Join Date: Dec 2001 Location: London Town Posts: 2,924	Eh? __________________ ICQ 1454 81 522 \|

04-05-2002, 12:35 PM	#23
bunky Confirmed User Join Date: Aug 2001 Location: Charlotte NC USA Posts: 902	i dont give a fuck how old you are, how long u were in school and all that other happy horse shit.. abcdefghijklmnopqrstuvwxyz = zyxvutsrqponmlkjihgfedcba! bunky oh and Bump! __________________ BoneProne 4 Life - BoneProne Family [insert title here]