[php] - howto update variable in external php file

[martinsc]

i need some quick php help...
let's say i have a file called x.php
with a few variables in it

$a = "2";
$b = "ddd";

and a file called y.php with

include 'x.php';

how could i get y.php to update the variable value in x.php?

thanks

[gornyhuy]

format c:

[Dirty F]

[martinsc]

thanks for the great help...

[RobbieRye]

If you are declaring constants such as "$a = "2";" then the only way to change it from another script would be to either redeclare it in y.php or re-write x.php using a file write.

There may be other options, but without a more in depth look at your complete script, it's difficult to form them.

[martinsc]

Thanks Robbie.
i'll look into file write.

[grumpy]

do you want to update the var in the file?

[who]

Originally Posted by Franck

[martinsc]

Originally Posted by grumpy

do you want to update the var in the file?

yes.......

[grumpy]

Originally Posted by martinsc

yes.......

then the only thing you can do is rewrite file

easiest thing is every var on a line like
2
3
4

then
$filename = "vars.txt";
$my_vars = file($filename);

$my_vars[0] will be 2

if you have changed the vars

just save the array.

[broke]

You need to open and read the file and then rewrite the contents. Something like this (has not been tested)...

PHP Code:

$new_value = "6";
$new_file = "";

$handle = @fopen("y.php", "r");
if ($handle) {
   while (!feof($handle)) {
       $buffer = fgets($handle, 4096);
       
       if(stristr($buffer,'$a' !hahahaha FALSE)){
          $new_file .= "$a = ".$new_value."\"";
       } else {
          $new_file .= $buffer;

   }
   fclose($handle);
}

$handle = @fopen("y.php", "w");
if($handle){
   fwrite($handle,$new_file);
} 


[martinsc]

thanks a lot guys.
i think i'll go with grumpy's idea...