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Old 06-04-2006, 09:33 PM   #1
Myst
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Math problem... solving for a variable thats an exponent

Umm so Im taking an actuarial science course for the spring
I cant for the life of me remember how to do this cause its been so long

how do you solve
1.08^-n + 1.08^-2n = 1
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Old 06-04-2006, 09:43 PM   #2
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irc://irc.efnet.net/math
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Old 06-04-2006, 09:46 PM   #3
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1+1=3 :-)
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Old 06-04-2006, 09:58 PM   #4
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Old 06-04-2006, 10:42 PM   #5
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1.08^-n + 1.08^-2n = 1

1 + 1.08^-n = 1 ( 1.08^n )

-1.08^n + 1.08^-n + 1 = 0

-1.08^n + 1 / ( 1.08^n ) + 1 = 0

-1.08^2n + 2 = 0

1.08^2n = 2

2n = log 2 / log 1.08

2n = 9.006468342

n = 4.503234171
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Old 06-04-2006, 11:07 PM   #6
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Quote:
Originally Posted by AmigoPorn
1.08^-n + 1.08^-2n = 1

1 + 1.08^-n = 1 ( 1.08^n )

-1.08^n + 1.08^-n + 1 = 0

-1.08^n + 1 / ( 1.08^n ) + 1 = 0

-1.08^2n + 2 = 0

1.08^2n = 2

2n = log 2 / log 1.08

2n = 9.006468342

n = 4.503234171

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