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06-04-2006, 09:33 PM
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#1 |
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Confirmed User
Join Date: Feb 2004
Location: Alberta, Canada
Posts: 4,707
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Math problem... solving for a variable thats an exponent
Umm so Im taking an actuarial science course for the spring
I cant for the life of me remember how to do this cause its been so long how do you solve 1.08^-n + 1.08^-2n = 1
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ICQ: 298-523-037 |
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06-04-2006, 09:43 PM
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#2 |
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Confirmed User
Industry Role:
Join Date: Nov 2005
Posts: 8,170
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irc://irc.efnet.net/math
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06-04-2006, 09:46 PM
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#3 |
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Too lazy to set a custom title
Join Date: Jul 2003
Location: Netherlands
Posts: 10,127
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1+1=3 :-)
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06-04-2006, 09:58 PM
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#4 |
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Confirmed User
Join Date: Sep 2005
Posts: 371
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-48.830373630755
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06-04-2006, 10:42 PM
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#5 |
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Too lazy to set a custom title
Join Date: Jul 2003
Location: Mexico - So far away from god, so close to the United States
Posts: 21,583
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1.08^-n + 1.08^-2n = 1
1 + 1.08^-n = 1 ( 1.08^n ) -1.08^n + 1.08^-n + 1 = 0 -1.08^n + 1 / ( 1.08^n ) + 1 = 0 -1.08^2n + 2 = 0 1.08^2n = 2 2n = log 2 / log 1.08 2n = 9.006468342 n = 4.503234171
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ICQ: 267899523 
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06-04-2006, 11:07 PM
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#6 | |
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Confirmed User
Join Date: Dec 2005
Posts: 247
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Quote:
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  Premium Level 1 Bandwith from Multiple Providers Lease-to-Own Dedicated Servers | Multiple Class C's Dave W: Dave [at] Tear2Hosting.com Sales Contact: Nick (Nick [at] Tear2Hosting.com) |
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