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Need help with Left Join (MySQL) Need help with Left Join (MySQL)
Discuss what's fucking going on, and which programs are best and worst. One-time "program" announcements from "established" webmasters are allowed.

 
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Old 10-20-2012, 08:12 AM   #1
MichaelP
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Need help with Left Join (MySQL)
Hey guys, I'm doing a bit of clean up in my stuff and I,m bulilding a new tool to manage my banners...

Here is what I try to accomplish (I know it's easy for a real programmer, which I'm not and never pretended to be)

Table programs : id , name ( ex : 22 , BabesMoney) ... +++

Table banner : id , program_id , site, (ex : 1 , 22 , Babes.Com) ... +++

Now here is the query which I play with... Not working but I know I'm close.. The query itself is pretty self explanatory

Code:
$query = "SELECT banner.*, programs.* FROM banner LEFT JOIN programs ON (program_id = programs.id, program = programs.program,) WHERE  blah, blah blah, meh meh meh... ";
So on the print, I want Program = BabesMoney instead of just 22

Thank in advance
Last edited by MichaelP; 10-20-2012 at 08:14 AM..
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Old 10-20-2012, 08:14 AM   #2
Vapid - BANNED FOR LIFE
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databases are matrices.
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Old 10-20-2012, 08:55 AM   #3
MichaelP
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Quote:
Originally Posted by pornopete View Post
You're probably better off hiring somebody than spending your time on this.
Well I'd do this if I couldn't do any of it, but now I'm stuck on a simple query, so I won't hire a programmer for a single line of code ...
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Old 10-20-2012, 08:58 AM   #4
donborno
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SELECT banner.id, programs.name, banner.site
FROM banner
LEFT JOIN programs ON banner.program_id = programs.id
WHERE blah, blah blah, meh meh meh...

Probably it's an INNER JOIN unless you have banners which do not reference a program
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Old 10-20-2012, 09:30 AM   #5
MichaelP
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Quote:
Originally Posted by donborno View Post
SELECT banner.id, programs.name, banner.site
FROM banner
LEFT JOIN programs ON banner.program_id = programs.id
WHERE blah, blah blah, meh meh meh...

Probably it's an INNER JOIN unless you have banners which do not reference a program
Not quite but Txs.

hey May I hire you for an hour or so? I can pay Paypal... I have a good name here and I want to keep it. Hit me up on ICQ pls @ 139036653
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Old 10-20-2012, 10:03 AM   #6
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Quote:
Originally Posted by MichaelP View Post
Not quite but Txs.

hey May I hire you for an hour or so? I can pay Paypal... I have a good name here and I want to keep it. Hit me up on ICQ pls @ 139036653
If the other guy is busy, icq me: 33375924, I can help out..
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Old 10-20-2012, 10:05 AM   #7
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$query = "SELECT banner.*, programs.* FROM banner LEFT JOIN programs ON (program_id = programs.id, program = programs.program,)

Do you actually have that comma before the close paren in there. Because that will screw it for you.

.
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Old 10-20-2012, 01:51 PM   #8
MichaelP
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Originally Posted by woj View Post
If the other guy is busy, icq me: 33375924, I can help out..
Thank you Woj for the nice help

Was very fast and effective. Will take yu for work again for sure.

A+
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Old 10-20-2012, 03:03 PM   #9
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Originally Posted by MichaelP View Post
Thank you Woj for the nice help

Was very fast and effective. Will take yu for work again for sure.

A+
Can't go wrong with WOJ

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Old 10-20-2012, 05:29 PM   #10
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Old 10-20-2012, 09:50 PM   #11
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Can't go wrong with WOJ

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Old 10-20-2012, 10:23 PM   #12
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Code:
SELECT banner.id AS banner_id, banner.program_id AS program_id, programs.site AS site_name FROM banner, programs WHERE banner.program_id = programs.id;
You have three columns returned -- banner_id, program_id, site_name.
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Old 10-21-2012, 01:30 AM   #13
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Quote:
Originally Posted by Kiopa_Matt View Post
Code:
SELECT banner.id AS banner_id, banner.program_id AS program_id, programs.site AS site_name FROM banner, programs WHERE banner.program_id = programs.id;
You have three columns returned -- banner_id, program_id, site_name.
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